已知最优差距时，只需约 log n 次遍历即可高效找出最优选项。

We investigate the sample-memory-pass trade-offs for pure exploration in multi-pass streaming multi-armed bandits (MABs) with the *a priori* knowledge of the optimality gap $Δ_{[2]}$. Here, and throughout, the optimality gap $Δ_{[i]}$ is defined as the mean reward gap between the best and the $i$-th best arms. A recent line of results by Jin, Huang, Tang, and Xiao [ICML'21] and Assadi and Wang [COLT'24] have shown that if there is no known $Δ_{[2]}$, a pass complexity of $Θ(\log(1/Δ_{[2]}))$ (up to $\log\log(1/Δ_{[2]})$ terms) is necessary and sufficient to obtain the *worst-case optimal* sample complexity of $O(n/Δ^{2}_{[2]})$ with a single-arm memory. However, our understanding of multi-pass algorithms with known $Δ_{[2]}$ is still limited. Here, the key open problem is how many passes are required to achieve the complexity, i.e., $O( \sum_{i=2}^{n}1/Δ^2_{[i]})$ arm pulls, with a sublinear memory size. In this work, we show that the ``right answer'' for the question is $Θ(\log{n})$ passes (up to $\log\log{n}$ terms). We first present a lower bound, showing that any algorithm that finds the best arm with slightly sublinear memory -- a memory of $o({n}/{\text{polylog}({n})})$ arms -- and $O(\sum_{i=2}^{n}{1}/{Δ^{2}_{[i]}}\cdot \log{(n)})$ arm pulls has to make $Ω(\frac{\log{n}}{\log\log{n}})$ passes over the stream. We then show a nearly-matching algorithm that assuming the knowledge of $Δ_{[2]}$, finds the best arm with $O( \sum_{i=2}^{n}1/Δ^2_{[i]} \cdot \log{n})$ arm pulls and a *single arm* memory.