利用无标签数据实现最优样本效率的鲁棒提升算法
Sample-Optimal Agnostic Boosting with Unlabeled Data
- 引入无标签数据辅助,设计高效鲁棒提升算法
- 在多项式数量无标签样本下达到ERM最优样本复杂度
- 适用于无标签数据免费的分布特定学习场景
Boosting 提供了一种实用且可证明有效的框架,可从不准确的经验规则构建高精度学习算法。它将样本高效的承诺扩展到直接经验风险最小化(ERM)无法高效实现的场景。在可实现设置中,Boosting 能在不牺牲样本效率的前提下提供计算上的优势。然而,在对抗性(agnostic)情况下,现有提升算法未能达到最优样本复杂度。本文揭示了一个此前未被探索的改进途径:利用无标签样本。我们设计了一种计算高效的对抗性提升算法,在获得多项式数量额外无标签样本的前提下,匹配 ERM 的样本复杂度。事实上,所需样本总数(含标签与无标签)不超过目前已知最优的对抗性提升算法——该结果从不更差,且只需极小比例的标签样本即可成功。这对学习理论中的对抗性提升应用尤为有利,这些应用常发生在无标签样本可免费获取的分布特定设置中。我们还探讨了该结果在强化学习中的其他应用。
原文摘要 · Abstract (English)
Boosting provides a practical and provably effective framework for constructing accurate learning algorithms from inaccurate rules of thumb. It extends the promise of sample-efficient learning to settings where direct Empirical Risk Minimization (ERM) may not be implementable efficiently. In the realizable setting, boosting is known to offer this computational reprieve without compromising on sample efficiency. However, in the agnostic case, existing boosting algorithms fall short of achieving the optimal sample complexity. This paper highlights an unexpected and previously unexplored avenue of improvement: unlabeled samples. We design a computationally efficient agnostic boosting algorithm that matches the sample complexity of ERM, given polynomially many additional unlabeled samples. In fact, we show that the total number of samples needed, unlabeled and labeled inclusive, is never more than that for the best known agnostic boosting algorithm -- so this result is never worse -- while only a vanishing fraction of these need to be labeled for the algorithm to succeed. This is particularly fortuitous for learning-theoretic applications of agnostic boosting, which often take place in the distribution-specific setting, where unlabeled samples can be availed for free. We detail other applications of this result in reinforcement learning.
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